A. 1
B. 11
C. 61
D. 121
If A = 6 and B = 5, what is the value of (A^2 - B ^2)^2?
2015-05-04 9:41 am
回答 (63)
2015-05-05 9:15 pm
D. 121
If A equals 6 and B equals 5...
(6^2 - 5^2)^2
((6 x 6) - (5 x 5))^2
(36 - 25)^2
11^2
11 x 11
121
If A equals 6 and B equals 5...
(6^2 - 5^2)^2
((6 x 6) - (5 x 5))^2
(36 - 25)^2
11^2
11 x 11
121
2015-05-04 9:48 am
Answer is D
(6^2 - 5^2)^2
= (36-25)^2
= 11^2
= 121
(6^2 - 5^2)^2
= (36-25)^2
= 11^2
= 121
2015-05-05 1:43 pm
If A = 6 and B = 5, what is the value of
(A^2 - B ^2)^2
= 11^2 (if A = 6 and B = 5)
Answer choice:
D. 121
(A^2 - B ^2)^2
= 11^2 (if A = 6 and B = 5)
Answer choice:
D. 121
2015-05-04 7:33 pm
Answer is D because [A^2 - B^2]^2 = [6^2 - 5^2]^2 = [(6-5)(6+5)]^2 = 11^2 = 121.
2015-05-05 8:25 am
D.121
2015-05-04 1:34 pm
Substitute a = 6 and b = 5 into the expression to get final answer of:
D. 121
D. 121
2015-05-06 3:41 pm
very much D.
2015-05-06 10:10 am
You have your formula, (A^2-B^2)^2
All you have to do is plug in your numbers.
(6^2-5^2)^2=
(36-25)^2=
11^2=
121
So the answer is D
All you have to do is plug in your numbers.
(6^2-5^2)^2=
(36-25)^2=
11^2=
121
So the answer is D
2015-05-06 2:31 am
You have your formula, (A^2-B^2)^2
All you have to do is plug in your numbers.
(6^2-5^2)^2=
(36-25)^2=
11^2=
121
So the answer is D.
All you have to do is plug in your numbers.
(6^2-5^2)^2=
(36-25)^2=
11^2=
121
So the answer is D.
2015-05-05 11:36 pm
D.121
2015-05-05 9:45 pm
(A^2 - B ^2)^2
= 11^2 (if A = 6 and B = 5)
Answer choice:
D. 121
= 11^2 (if A = 6 and B = 5)
Answer choice:
D. 121
2015-05-05 6:38 pm
121 is the answer
2015-05-05 4:28 pm
(6^2 - 5^2)^2
(36 - 25)^2
(11)^2
121
(36 - 25)^2
(11)^2
121
2015-05-05 4:55 pm
(A^2 - B^2)^2 = (6^2 - 5^2)^2
(A^2 - B^2)^2 = (36 - 25)^2
(A^2 - B^2)^2 = (11)^2
(A^2 - B^2)^2 = 11^2
(A^2 - B^2)^2 = 121
Therefore, the answer is D.
(A^2 - B^2)^2 = (36 - 25)^2
(A^2 - B^2)^2 = (11)^2
(A^2 - B^2)^2 = 11^2
(A^2 - B^2)^2 = 121
Therefore, the answer is D.
2015-05-04 9:53 am
You have :
----------------
Let P = ( A^2 - B^2 )^2 with A = 6 and B = 5
P = ( 6^2 - 5^2 )^2
P = ( 36 - 25 )^2
P = ( 11 )^2 = 121 <---------------------
----------------
Let P = ( A^2 - B^2 )^2 with A = 6 and B = 5
P = ( 6^2 - 5^2 )^2
P = ( 36 - 25 )^2
P = ( 11 )^2 = 121 <---------------------
2015-05-08 1:07 pm
D. 121
2015-05-08 10:19 am
f A equals 6 and B equals 5...
(6^2 - 5^2)^2
((6 x 6) - (5 x 5))^2
(36 - 25)^2
11^2
11 x 11
121
(6^2 - 5^2)^2
((6 x 6) - (5 x 5))^2
(36 - 25)^2
11^2
11 x 11
121
2015-05-07 2:55 pm
(((A^2)-(B^2))^2)
((6^2)-(5^2)) ^2
(36-25)^2
(11)^2
121
((6^2)-(5^2)) ^2
(36-25)^2
(11)^2
121
2015-05-07 11:31 am
d. 121
2015-05-07 10:59 am
D. 121
2015-05-07 7:53 am
d
2015-05-07 4:52 am
D.121
2015-05-07 3:28 am
(36-25)^2=121
2015-05-07 2:17 am
121. Use the order of operations. You'll do what's in the parenthesis first, starting with the squares and then subtraction. so 36 - 25 = 11, then square 11, so 11*11 = 121!
2015-05-07 1:13 am
):/)7/)/)/6/6/
2015-05-07 12:58 am
121
2015-05-06 9:54 pm
D. 121
2015-05-06 9:53 pm
D
2015-05-06 9:07 pm
You have :
--------------
P = f(A,B) = ( A^2 - B^2 )^1/2
P = [ 6^2 - 5^2 ]^2
P = [ 36 - 25 ]^2 = [ 11 ]^2 = 121 <----------------
--------------
P = f(A,B) = ( A^2 - B^2 )^1/2
P = [ 6^2 - 5^2 ]^2
P = [ 36 - 25 ]^2 = [ 11 ]^2 = 121 <----------------
2015-05-06 9:01 pm
OK, let's get tricky (and do it the complicated way)
a^2 - b^2 is a difference of squares
the factors are (a+b)(a-b)
therefore, we can rewrite as
[(a+b)(a-b)]^2
a=6 and b=5
gives us
a+b = 11
a-b = 1
their product (a+b)(a-b) = 11 * 1 = 11
this gets squared
11^2 = 11 * 11 = ...
You know that 11*11 is going to be bigger than 10*10,
and that is equal to 100.
Therefore, without doing the calculation, you can eliminate any choice that is less than 100.
a^2 - b^2 is a difference of squares
the factors are (a+b)(a-b)
therefore, we can rewrite as
[(a+b)(a-b)]^2
a=6 and b=5
gives us
a+b = 11
a-b = 1
their product (a+b)(a-b) = 11 * 1 = 11
this gets squared
11^2 = 11 * 11 = ...
You know that 11*11 is going to be bigger than 10*10,
and that is equal to 100.
Therefore, without doing the calculation, you can eliminate any choice that is less than 100.
2015-05-06 8:46 pm
[(6)^2-(5)^2]^2
[36-25]^2
11^2
121
Don't forget to solve what's in the parenthesis first.
[36-25]^2
11^2
121
Don't forget to solve what's in the parenthesis first.
2015-05-06 8:43 pm
(6^2-5^2)^2
((6x6)-(5x5))^2
(36-25)^2
36-25=11
(11)^2
11x11=121
((6x6)-(5x5))^2
(36-25)^2
36-25=11
(11)^2
11x11=121
2015-05-06 8:37 pm
D = 121
2015-05-06 7:08 pm
11
2015-05-06 6:17 pm
121
2015-05-06 5:42 pm
121
2015-05-06 5:06 pm
121
2015-05-06 4:54 pm
(A^2 - B ^2)^2, here if you substitute A and B by 6 and 5, you get (36-25)^2= 121 which is D in your option. However, for bigger values, you could write (A^2 - B ^2)^2= {(A+B)(A-B)}^2= (A+B)^2.(A-B)^2
2015-05-06 4:24 pm
its 121
2015-05-06 4:09 pm
(6^2 - 5^2)^2
= (36 - 25)^2
= 11^2
= 121
= (36 - 25)^2
= 11^2
= 121
2015-05-06 3:17 pm
=(6^2 - 5^2)^2
=(36 - 25)^2
= 11^2
=121 answer//
Answer is D. 121..//
=(36 - 25)^2
= 11^2
=121 answer//
Answer is D. 121..//
2015-05-06 3:13 pm
(A^2 - B ^2)^2
(36 - 25)^2
11^2 = 121
(36 - 25)^2
11^2 = 121
2015-05-06 1:12 pm
((6^2) - (5^2))^2
(36-25)^2
11^2
=121
so the answer will be d
(36-25)^2
11^2
=121
so the answer will be d
2015-05-06 11:31 am
(A^2- B^2)^2 = (( A +B) ( A-B) )^2 = (( 6+5) ( 6-5))^2 = (11*1)^2 = 11^2 = 121
ANSWER is D
ANSWER is D
2015-05-06 7:49 am
D
2015-05-06 5:11 am
D
2015-05-06 4:41 am
It's 121, and I figured that out in my head.
2015-05-06 4:35 am
Answer is D .
2015-05-06 1:15 am
**A=6 and B=5**
(A^2-B^2)^2
= (6^2-5^2)^2
=(36-25)^2
=(11)^2
=D. 121
(A^2-B^2)^2
= (6^2-5^2)^2
=(36-25)^2
=(11)^2
=D. 121
2015-05-05 8:12 pm
121
2015-05-05 4:29 pm
121
2015-05-05 2:39 pm
D. 121
2015-05-05 1:11 pm
D. 121
2015-05-05 9:45 am
One Hundred Twenty One. :) Letter D.
2015-05-05 7:44 am
Answer is D.121
2015-05-05 7:30 am
36-25= 11
11 square= 121
11 square= 121
2015-05-04 7:47 pm
(6^2 - 5^2)^2
(36 - 25)^2
(11)^2
D. 121
(36 - 25)^2
(11)^2
D. 121
2015-05-04 7:18 pm
D
2015-05-04 6:29 pm
Choice D. 121 is correct.
2015-05-04 5:28 pm
121 just plug the numbers to the formula
2015-05-04 1:08 pm
121
2015-05-04 9:46 am
(6^2 - 5^2)^2
(36-25)^2
(11)^2
121
(36-25)^2
(11)^2
121
2015-05-04 9:42 am
D. 121
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150504014147AAm6svf