A phosphorus oxide has an empirical formula of PxOy and 56.36% phosphorus by mass . What is the values of x anf y?
回答 (1)
2015-05-06 2:11 am
moles of P in 100 g of the oxide = 56.36 / MM of P = 56.36 / 30.97 = 1.820 moles
mass of O in 100 g = 100-56.36 = 43.64 g or 43.64 / 16 moles = 2.73 moles
molar ratio of P:O = 1.820: 2.73
to simplify the ratio we divide by the smaller number and we get 1:1.5
now we multiply by 2 to get whole number ratios ... 2:3
empirical formula is P2O3
mass of O in 100 g = 100-56.36 = 43.64 g or 43.64 / 16 moles = 2.73 moles
molar ratio of P:O = 1.820: 2.73
to simplify the ratio we divide by the smaller number and we get 1:1.5
now we multiply by 2 to get whole number ratios ... 2:3
empirical formula is P2O3
收錄日期: 2021-05-03 03:25:31
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