Vertical forces in equilibrium:
T.cos(theta) + 30.cos(65) = 45 -------------- (1)
where T is the tension in AC
Horizontal forces in equilibrium:
T.sin(theta) = 30.sin(65) ------------- (2)
From (1) and (2),
Can you solve for T and angle (theta)?
聯立方程的問題
2015-05-02 2:26 am
回答 (1)
2015-05-02 2:51 am
✔ 最佳答案
{ T cos θ + 30 cos(65°) = 45{ T sin θ = 30 sin(65°)
{ T cos θ = 45 - 30 cos(65°) ...(B)
{ T sin θ = 30 sin(65°) ... (A)
(A) ÷ (B) gives
tan θ = 30 sin(65°) / [45 - 30 cos(65°)]
θ = tan⁻¹{ 30 sin(65°) / [45 - 30 cos(65°)] }
θ = 40.07099112°
Put back to (B),
T = 30 sin(65°) / sin θ
T = 42.23660371
2015-05-01 18:52:20 補充：
"Put back to (B)" should be "Put back to (A)".
收錄日期: 2021-04-21 22:43:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150501000051KK00058