1) x^2-6x=-2(leave the answer in surd form)
2a) Solve 2y^2+3y+1=0. I know the answer is y=0.5 or y=-1
2b) Using the result of (a), solve 2x^(2/3)+3x^(1/3)+1=0
唔識做功課64
2015-04-29 4:22 am
回答 (2)
2015-04-29 5:17 am
2015-04-29 9:41 pm
2a) 2y^2+3y+1=0
2y^2+3y=-1
2y+3=-y
2y=-y-3
3y=-3
y=-1
I would answer the rest at adout 4:30PM today...
2y^2+3y=-1
2y+3=-y
2y=-y-3
3y=-3
y=-1
I would answer the rest at adout 4:30PM today...
參考: me
收錄日期: 2021-04-15 19:12:42
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