The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent.?

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2015-04-27 11:27 pm

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A 7.83-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by 38.6 mL of a 0.115 M aqueous solution of KBrO3(aq). The unbalanced equation for the reaction is BrO3-(aq)+Sb+3(aq)-->Br-(aq)+Sb+5(aq) Calculate the amount of antimony in the sample and its percentage in the ore

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Roger the Mole

2015-04-28 1:05 am

BrO3{-} + 3 Sb{3+} + 6 H{+} → Br{-} + 3 Sb{5+} + 3 H2O

(0.0386 L) x (0.115 mol/L BrO3{-}) x (3 mol Sb / 1 mol BrO3{-}) x (121.760 g Sb/mol) = 1.62 g Sb

(1.62 g Sb) / (7.83 g) = 0.207 = 20.7% Sb

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