✔ 最佳答案
1、若xyz不等於0,且2/x=6/y=7/z,則(x+y+z):y之比值為_
Sol
2/x=6/y=7/z
2/x=6/y=7/z=(2+6+7)/(x+y+z)=15/(x+y+z)
(x+y+z):y=15:6=5/2
2、設2x:5y:3z=1:3:2,且x+2y+z=142,則x+y+z=__
Sol
2x:5y:3z=1:3:2
2x/1=5y/3=3z/2
2x/30=5y/90=3z/60
x/15=y/18=z/20
x/15=2y/36=z/20
x/15=2y/36=z/20=(x+2y+z)/(15+36+20)=142/71=2
x=30,y=36,z=40
x+y+z=106
3、甲、乙兩數的差、和與乘積的連比為1:5:24,且甲數大於乙數,則甲數為_
Sol(甲-乙):(甲+乙):甲*乙=1:5:24(甲-乙)/1=(甲+乙)/5=甲*乙/24(甲-乙)/1=(甲+乙)/5=[(甲-乙)+(甲+乙)]/(1+5)=甲/3(甲-乙)/1=(甲+乙)/5=[(甲-乙)-(甲+乙)]/(1-5)=乙/2So甲/3=乙/2=k甲=3k,乙=2k甲>乙
k>0
k:5k:6k^2=1:5:24
1:5:6k=1:5:24
k=4
甲=12
4、若(x+3)/x=(y+5)/y=(z+7)/z,則x:y:z=?
Sol
(x+3)/x=(y+5)/y=(z+7)/z
1+3/x=1+5/y=1+7/z
3/x=5/y=7/z
x:y:z=3:5:7
5、若2x:3=y:4=3z:5,且xyz不等於0,求
(1)x:y:z=?
Sol
2x:3=y:4=3z:5
2x/3=y/4=3z/5
2x/18=y/24=3z/30
x/9=y/24=z/10
x:y:z=9:24:10
(2) (-4x+y+z):(x-2y+4z)之比值為何?
Sol
x/9=y/24=z/10
x/9=-4x/(-36)=y/24=z/10=(-4x+y+z)/(-36+24+10)=(-4x+y+z)/(-2)
x/9=(-2y)/(-48)=4z/40=(x-2y+4z)/(9-48+40)=(x-2y+4z)/1
So
(-4x+y+z)/(-2)=(x-2y+4z)/1
(-4x+y+z):(x-2y+4z)=-2