find the exact value of [tan25+tan50] / [1-tan25tan50]?
回答 (2)
2015-04-19 10:58 pm
tan(A+B)= (tanA+tanB) / (1-tanA*tanB) is a formula and your question satisfy it.
so, [tan25+tan50] / [1-tan25*tan50] = tan [25+50] = tan75
so, [tan25+tan50] / [1-tan25*tan50] = tan [25+50] = tan75
2015-04-19 10:45 pm
[tan25+tan50] / [1-tan25tan50] = tan(75) = tan(30 + 45) = ...you can continue
收錄日期: 2021-05-01 20:30:02
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