2014 ICT past paper問題 (高手請入)

2015-04-15 5:03 am
小女最近做緊2014嘅ICT past paper
但係有啲題目解吾明
請咁多位詳細指點下(我有啲蠢sorry┬ ┬)

1)將下列以8位二進制補碼表示的數字加1,
哪一個數字會引發溢岀誤差?
A.01111111
B.10000000
C.10000001
D.11111111
答案係[A],但係我吾明點解┬ ┬

2)在某電腦內,
10個位元用作用戶識別號碼,
54個位元用作別名.
此系統內最多可有多少個戶口?
答案係[1024],請問點計?┬ ┬

3)bmp轉換成jpg時,
解像度會吾會變?

4)SMTP,IMAP,POP係咩?┬ ┬

5)小美喺機場用wifi,
佢收到嘅wifi格數好爆,
但係上網速度好慢,
點解會咁?

以上就係我全部問題啦┬ ┬
感激萬分♥♥

回答 (1)

2015-04-16 6:53 am
✔ 最佳答案
1) first 8 bit code have the maximum number of codes = 2^8 =256
then the range will be 127(01111111)~ -128(10000000)
A=127
B=128(out of range)
C=129(out of range)
D=255(out of range)

then A(127) +1 =128= out of range, so answer is A.

2)ans = 2^10=1024
because 用戶識別號碼 =number of accounts
54別名 is not same to have 54 accounts

3)yes and lower a bit than the original one
because jpg use loosy compression skill can have smaller file size

4) SMTP=Simple Mail Transfer Protocol
IMAP=Internet Message Access Protocol
POP=Post Office Protocol
some skill used of email

5)maybe the speed that the wifi provide is low actually

2015-04-15 22:53:59 補充:
我ICT用英文教,所以唔太明你中文sor
參考: self


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