Probabilities thanks

Picture 1:
P(exactly 1 tail) = 3*1/2*1/2*1/2=3/8

Picture 2:
Q1
P(one tail ^ even number) = 1/2*1/2= 1/4

Q2
Brown = 150
Blue = 35
Green = 350-150-35 = 165

i) P(blue) = 35/350
ii) P(green) = 165/350

Picture 3:
Q1
Okay, 2-digit number that is divisible by 12.
12*x < 100
x < 8 R 4
That means there are 8 possible 2-digit numbers that are divisible by 12.
Sample space will be:
10.....19
20.....29
.........
.........
90......99
There will be 90 #s in sample space.

P(#s divisible by 12) = 8/90

Q2
Total tosses = 100
i) P(even) = (17+22+12)/100=51/100
ii) P(#>4) = (18+12)/100 = 30/100
iii) P(#>3) = (22+18+12)/100 = 52/100

Picture 4:
Try to use to ratio of red and green balls from the sample. Then it shouldn't be hard to solve.