https://upload.iniiter.com//img/2015/4/c948445b1e11763125262486d794aa6115fd911056ca.jpg
https://upload.iniiter.com//img/2015/4/c948445b1e11763121212486d794aa6115fae04b08c77bc5.jpg
Thank.
中四數學 MC.
2015-04-12 8:15 pm
回答 (3)
2015-04-13 12:43 am
✔ 最佳答案
1.D
5(x+3)+1
=5x+16
2.A
4/(x²+2x-3) - 3/(x²+x-2)
=4/[(x+3)(x-1)] - 3/[(x+2)(x-1)]
=[4(x+2) - 3(x+3)]/[(x+3)(x+2)(x-1)]
=[4x+8 - 3x-9]/[(x+3)(x+2)(x-1)]
=[x-1]/[(x+3)(x+2)(x-1)]
=1/[(x+3)(x+2)]
3.B
4.A
2015-04-13 1:10 am
1
f(x)=(5x+1)Q(x)
f(x+3)=[5(x+3)+1]Q(x+3)
f(x+3)=(5x+15+1)Q(x+3)
f(x+3)=(5x+16)Q(x+3)
ans is D
2
4/(x^2 +2x -3) -3/(x^2 +x-2)
=4/[(x-1)(x+3)] -3/[(x-1)(x+2)]
=[4(x+2)-3(x+3)]/[(x-1)(x+2)(x+3)]
=(4x+8-3x-9)/[(x-1)(x+2)(x+3)]
=(x-1)/[(x-1)(x+2)(x+3)]
=1/[(x+2)(x+3)]
ans is A
3
ans is C
4
b>0>k
ans is A
f(x)=(5x+1)Q(x)
f(x+3)=[5(x+3)+1]Q(x+3)
f(x+3)=(5x+15+1)Q(x+3)
f(x+3)=(5x+16)Q(x+3)
ans is D
2
4/(x^2 +2x -3) -3/(x^2 +x-2)
=4/[(x-1)(x+3)] -3/[(x-1)(x+2)]
=[4(x+2)-3(x+3)]/[(x-1)(x+2)(x+3)]
=(4x+8-3x-9)/[(x-1)(x+2)(x+3)]
=(x-1)/[(x-1)(x+2)(x+3)]
=1/[(x+2)(x+3)]
ans is A
3
ans is C
4
b>0>k
ans is A
2015-04-12 9:56 pm
相片連結好像有問題？
收錄日期: 2021-04-15 19:06:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150412000051KK00021