can someone explain to me how to factor 2597 to get (7 square root 53)^2?
回答 (3)
2015-03-21 10:09 pm
2597 = 7*7*53
= 7² • 53
√(7² • 53) = √7² • √53
√ of anything squared is the number itself.
√7² • √53 = 7 • √53
which we write as 7√53
= 7² • 53
√(7² • 53) = √7² • √53
√ of anything squared is the number itself.
√7² • √53 = 7 • √53
which we write as 7√53
2015-03-21 9:49 pm
2597
= 7² × 53
= (7 × √53)²
= 7² × 53
= (7 × √53)²
2015-03-21 9:48 pm
2597 can be reduced to the prime factors
{ 7^2 , 53}
(7 Sqrt[53])^2
=
7^2 x 53
{ 7^2 , 53}
(7 Sqrt[53])^2
=
7^2 x 53
收錄日期: 2021-05-01 15:18:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150321134417AAwonAz