物理 --物態的改變

Heat required to raise the temperature of 1 kg water from 0'C to 100'C
= 1 x 4200 x 100 J = 420 000 J
where 4200 J/kg is the specific heat capacity of water

Let m be the mass of 100'C steam required.
hence, m.(2260 x 10^3) = 420 000
where 2260 x 10^3 J/kg is the latent heat of vapourization of water

SOlve for m gives m = 0.1858 kg = 186 g

(2260000)mass of gas=4200x1000
mass of gas=0.186
4200:Specific heat capacity :c=dT/dS (as I remember) which S is entropy
2260000 is the amount of energy release for 1kg of gas

可不可以一條式去表達