Find the perimeter of a rectangle if its length is (4x+7) and its width is (x-3) units.?
回答 (2)
2015-02-24 12:06 am
The perimeter of a rectangle is:
P = 2(length + width)
that doesn't seem too difficult...at least you could "try !"
P = 2[(4x + 7) + (x - 3)] = 2[5x + 4] = (10x + 8) units
you should go to your teacher for help...now !!
P = 2(length + width)
that doesn't seem too difficult...at least you could "try !"
P = 2[(4x + 7) + (x - 3)] = 2[5x + 4] = (10x + 8) units
you should go to your teacher for help...now !!
2015-02-24 12:04 am
perimeter = 2×length + 2×width
= 2(4x+7) + 2(x-3)
= 8x+14 + 2x-6
= 10x+8
= 2(4x+7) + 2(x-3)
= 8x+14 + 2x-6
= 10x+8
收錄日期: 2021-04-21 01:22:28
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https://hk.answers.yahoo.com/question/index?qid=20150223160400AAhuYXy