A square has a perimeter of 4x + 12. What is its area?
So just the equation. The answer is (x^2 + 6x + 9)units ^2
I'm not really sure how to figure this out and need help. It would be great if you could show me your working out as well please! Thank you so much
How to solve this easy algebraic question?
2015-02-23 6:05 am
回答 (4)
2015-02-23 6:08 am
✔ 最佳答案
((4x + 12)/4)²= (x + 3)²
= (x + 3)(x + 3)
= x(x + 3) + 3(x + 3)
= x² + 3x + 3x + 9
= x² + 6x + 9 <-- Answer
Though, it would almost be simpler to express it in it's factored form (x + 3)²
2015-02-23 6:41 am
Perimeter of a square = 4 x side
So side = (4x+12)/4 = (x+3)
Area = side^2 = (x+3)^2 = x^2 + 6x + 9
So side = (4x+12)/4 = (x+3)
Area = side^2 = (x+3)^2 = x^2 + 6x + 9
2015-02-23 6:11 am
s = (4x + 12) / 4
s = x + 3
s^2 = A
(x + 3)^2 = A
(x + 3)(x + 3) = A
x^2 + 3x + 3x + 9 = A
x^2 + 6x + 9 = A
area = x^2 + 6x + 9 units^2
s = x + 3
s^2 = A
(x + 3)^2 = A
(x + 3)(x + 3) = A
x^2 + 3x + 3x + 9 = A
x^2 + 6x + 9 = A
area = x^2 + 6x + 9 units^2
2015-02-23 6:07 am
P = 4 sides---> side = P / 4 and area = side²
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