指數方程式求值應用題x1

2015-02-16 8:58 am
這題2的2次方或三次方再怎麼乘也不會是6,就是它們不能化為底數一樣,該怎麼算?請教教我囉~謝謝~~

題目在此: http://imgur.com/P5DWD93

回答 (3)

2015-02-16 9:34 am
✔ 最佳答案
6^(1/3)• 15^(1/4) • 20^(-1/2)
= (2 × 3)^(1/3) • (3 × 5)^(1/4) • (2^2 × 5)^(-1/2)
= 2^(1/3) • 3^(1/3) • 3^(1/4) • 5^(1/4) • 2^(-1) • 5^(-1/2)
= 2^[(1/3)-1] • 3^[(1/3)+(1/4)] • 5^[(1/4)-(1/2)]
= 2^(-2/3) • 3^(7/12) • 5^(-1/2)

2^x • 3^y • 5^z = 6^(1/3) • 15^(1/4) • 20^(-1/2)
2^x • 3^y • 5^z = 2^(-2/3) • 3^(7/12) • 5^(-1/2)
所以 x = -2/3, y = 7/12, z = -1/2

x • y • z
= (-2/3) • (7/12) • (-1/2)
= 7/72 ...... 答案選(D)
2015-02-17 8:45 am
土扁:
謝謝你幫我回答,不過我發現你有一個小地方打錯了,是
= 2^(-2/3) • 3^(7/12) • 5^(-1/4) 拉~~所以 z = -1/4,不過答案沒錯~
2015-02-16 9:18 am
把6、15、20做質因數分解
其實只有2、3、5而已~


收錄日期: 2021-04-15 18:16:19
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