solve (yk+1)^2-(yk)^2=1
yk+1= the (k+1)th term of y
yk= the kth term of y
收錄日期: 2021-04-29 00:07:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150214000051KK00098