未教就測驗...我都唔知講緊乜!!!
For 0度 ≤ b ≥ 90度,the maximum value of 2 / (3 + sin ^2 b ) is
唔識做功課47
2015-02-11 1:52 am
回答 (2)
2015-02-11 5:13 am
✔ 最佳答案
0度 ≤ b ≤ 90度sin 0度 ≤ sin b ≤ sin 90
0 ≤ sin b ≤ 1
0 ≤ sin^2 b ≤ 1
3 ≤ 3 + sin^2 b ≤ 3 + 1
1/3 ≥ 1/(3 + sin^2 b) ≥ 1/4
2/3 ≥ 2/(3 + sin^2 b) ≥ 2/4
2/3 ≥ 2/(3 + sin^2 b) ≥ 1/2∴ the maximum value of 2/(3 + sin^2 b) is 2/3.
2015-02-11 3:47 am
你其實可以問老師,而且你問題有小小不清晰=.=
收錄日期: 2021-04-15 18:18:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150210000051KK00052