A car proceeds along a circular path of radius R = 300 m centered
at the origin. Starting at rest, its speed increases at a rate of t m/s2. Find
the acceleration vector a at time t = 3 s and determine its decomposition
into normal and tangential components.
Help please!! Math Question?
2015-02-10 7:17 am
回答 (1)
2015-02-10 7:59 am
@ t = 3 , at = 3m/sec^2
average tangential acceleration ata = at/2 = 3/2 = 1.5 m/sec^2
V = ata*t = 1.5*3 = 4.5 m/sec
ac = V^2/r = 0.068 m/sec^2
a = √ac^2+at^2 = √3^2+0.068^2 = 3.001 m/sec^2
average tangential acceleration ata = at/2 = 3/2 = 1.5 m/sec^2
V = ata*t = 1.5*3 = 4.5 m/sec
ac = V^2/r = 0.068 m/sec^2
a = √ac^2+at^2 = √3^2+0.068^2 = 3.001 m/sec^2
收錄日期: 2021-04-21 01:19:09
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