Please show all clear steps, thank you.
Ex1. Solve for x
a) x^5 = 20
Ex2. Find the value of [log(4/3)base 2] - [log(5/4)base 2] + [log(15/8)base 2
Ex3. If logX = a, logY = b and logZ = c, express the following in terms of a, b, and c.
a) log[(x^(3)y^(2))/(z^(1/2))]
b) [logx^(3)y^(2)]/[logz^(1/2)]
I really need help, thank you. ;)
Logarithms要幫助
2015-02-03 1:46 pm
回答 (1)
2015-02-03 5:50 pm
✔ 最佳答案
x^5 = 20x = 20^(1/5) = 1.82
[log (4/3) base 2] - [log (5/4) base 2] + [log (15/8) base 2]
= [log (4/3) / (5/4) x (15/8) base 2]
= [log 2 base 2]
= 1
log [(x^3)(y^2)/(z^(1/2))]
= log x^3 + log y^2 - log z^(1/2)
= 3log x + 2log y - (1/2)log z
= 3a + 2b - c/2
log [(x^3)(y^2)] / [log z^(1/2)]
= (log x^3 + log y^2) / [(1/2) log z]
= (3log x + 2log y) / [(1/2) log z]
= (3a + 2b) / (c/2)
= (6a + 4b) / c
參考: knowledge
收錄日期: 2021-04-15 18:12:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150203000051KK00012