Calculate the energy in joules to heat 895 g of mercury from 37.0 C to 42.0 C. The specific heat capacity of Hg(l) is 0.139 J/g.C.?
回答 (6)
2015-02-05 4:07 am
Haha, I wonder why it is a Chemistry Question. Obviously, it's the Physics topic, Heat!
Name: Mercury
Symbol: Hg
Atomic Number: 80
Melting Point: -38.87 °C
Boiling Point: 356.58 °C
Special TIP(s): Both specific latent heat of fusion and vaporization are not used. Only specific heat capacity is used! Temperature change: (37.0 C to 42.0 C)
E = mc (delta)T
E = 895.0 x 0.139 x (42.0-37.0)
E= 622.025 J
Name: Mercury
Symbol: Hg
Atomic Number: 80
Melting Point: -38.87 °C
Boiling Point: 356.58 °C
Special TIP(s): Both specific latent heat of fusion and vaporization are not used. Only specific heat capacity is used! Temperature change: (37.0 C to 42.0 C)
E = mc (delta)T
E = 895.0 x 0.139 x (42.0-37.0)
E= 622.025 J
2015-02-04 6:55 am
mass 895g
initial temp 37.0C
final temp 42.0C
temperature change ∆T (initial temp -final temp)
42.0C-35.0C=5.0c
specific heat capacity Hg(l) 0.139J/gC
Quantity of heat(q)= mass of the sample(m)×specific heat capacity (C)× change in temperature(∆T)
q=MC∆T
therefore 895g×0.139J/g.C×5.0C= 622.025J (answer)
initial temp 37.0C
final temp 42.0C
temperature change ∆T (initial temp -final temp)
42.0C-35.0C=5.0c
specific heat capacity Hg(l) 0.139J/gC
Quantity of heat(q)= mass of the sample(m)×specific heat capacity (C)× change in temperature(∆T)
q=MC∆T
therefore 895g×0.139J/g.C×5.0C= 622.025J (answer)
2015-02-01 1:20 am
OK, since you know that the energy required is mass * specific heat * change in temperature, and you know the mass, you know the specific heat, and you know the change in temperature, then your question is...?
2015-02-01 1:23 am
Randy P nailed it.... q=mc(deltaT)
2015-02-01 1:23 am
Calculate the energy needed to warm 895g of Hg from 37C to 42C.
q = mcΔT ........... where q is the quantity of heat, m is the mass, c is the specific heat capacity and ΔT is the change in temperature. Simply plug and chug:
q = 895g x 0.139 J/gC x 5.0C
q = 622 J
q = mcΔT ........... where q is the quantity of heat, m is the mass, c is the specific heat capacity and ΔT is the change in temperature. Simply plug and chug:
q = 895g x 0.139 J/gC x 5.0C
q = 622 J
2015-02-01 1:24 am
(0.139 J/g.C) x (895 g) x (42.0 - 37.0) C = 622 J
收錄日期: 2021-05-02 11:37:09
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