✔ 最佳答案
Pr(1st ace and 2nd ace and 3rd king)
= Pr(1st ace) * Pr(2nd ace and 3rd king | 1st ace)
= Pr(1st ace) * Pr(2nd ace | 1st ace) * Pr(3rd king | 1st ace and 2nd ace)
= (4/52) * (3/51) * (4/50)
= (1/13) * (1/17) * (2/25)
= 2/5525
2015-02-01 17:30:12 補充:
嗚謝 sioieng 提供另解:
The required probability
= Pr(2 aces from 52 cards with 4 aces) × Pr(a king from 50 cards with 4 kings)
= [C(4,2) / C(52,2)] × [C(4, 1) / C(50, 1)]
= [(4!/2!2!) / (52!/50!2!)] × [(4!/1!3!) / (50!/1!49!)]
= [(4 × 3) / (52 × 51)] × [4 / 50]
= [(1 × 1) / (13 × 17)] × [2 / 25]
2015-02-01 17:30:28 補充:
= 2/5525
2015-02-01 17:30:52 補充:
嗚謝 土扁 師兄 提供另解:
The required probability
= Pr(1 ace from 52 cards with 4 aces) × Pr(1 ace from 51 cards with 3 aces) × Pr(a king from 50 cards with 4 kings)
= (4/52) × (3/51) × (4/50)
= (1/13) × (1/17) × (2/25)
= 2/5525