更新1:
HELP I HAVE A TEST TOMORROW
Solve the following system of equations algebraically for all values of x and y. y=x^2+2x-8 y=2x+1 Please show steps?
回答 (1)
2015-01-25 6:57 pm
x^2 + 2x - 8 = 2x + 1
x^2 = 9
x = 3 or x = -3
y = 2(3) + 1 = 7 or y = 2(-3) + 1 = -5
(x, y) = (3, 7) or (x, y) = (-3, -5)
x^2 = 9
x = 3 or x = -3
y = 2(3) + 1 = 7 or y = 2(-3) + 1 = -5
(x, y) = (3, 7) or (x, y) = (-3, -5)
收錄日期: 2021-05-01 16:28:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150125105622AAq5UlR