Fin the remaining trigonometric ratios
csc θ= - 4/3, 3π/2 < θ < 2π
Please provide solution
Thanks
Math Calculus
2015-01-14 11:01 am
回答 (1)
2015-01-14 4:37 pm
✔ 最佳答案
Solutions:since 3π/2 < θ < 2π,
sin θ < 0, cos θ > 0, tan θ < 0, sec θ > 0, cot θ < 0.
sin θ = 1 / csc θ = - 3 / 4
cos θ = √(1 - sin2θ) = √7 / 4
tan θ = sin θ / cos θ = - 3 / √7 = - 3√7 / 7
cot θ = 1 / tan θ = - √7 / 3
sec θ = 1 / cos θ = 4 / √7 = 4√7 / 7
參考: knowledge
收錄日期: 2021-04-28 14:22:43
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