nth term = (n + 1)th term - 6
(n + 1)th term = nth term + 6
So the common difference = 6
Let a be the first term,
28/2[2a+(27)(6)]=1624
a=-23
So the ans is -23
For a certain sequence,nth term=(n+1)th term-6,Sum of first 28 terms=1624,
Find the 1st term of the sequence
Sol
a(n)=a(n-1)+6
d=6
a(16)=a(1)+15d=a(1)+90
1624=[a(1)+a(1)+90]*28/2
116=2a(1)+90
a(1)=13