The element Antimony,Sb has a relative atomic mass of 121.75 amu .
It consists of two isotopes (121, 51) Sb and (123,51) State the number of Protons, Neutrons and Electrons in each isotope.
What is the relative abundance(percentage) of 121 Sb in a natural sample of this element?
Chemistry help?
2015-01-08 9:50 am
回答 (1)
2015-01-08 10:50 am
Let the relative abundance of 121 Sb be x
121x+123(1-x)=121.75
123-121.75=(123-121)x
1.25=2x
x=0.625
x=62.5%
Done, just got my chemistry exam including this today. :p
121x+123(1-x)=121.75
123-121.75=(123-121)x
1.25=2x
x=0.625
x=62.5%
Done, just got my chemistry exam including this today. :p
收錄日期: 2021-04-15 17:49:19
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