唔識做功課40

2015-01-09 2:37 am
When the polynomials F(x) of degree 3 is divided by x-1, the remainder is -1. When F(x) is divided by x+1, the remainder is-5 . If F(x) is divided by (x-1)(x+1), the remainder is ax+b, where a and b are constants. Find the value of a and b.

回答 (1)

2015-01-09 3:22 am
✔ 最佳答案
Since the remainder is - 1 and - 5 when F(x) is divided by x - 1 and x + 1,
F(1) = - 1 and F(- 1) = - 5F(x) = Q(x) (x - 1) (x + 1) + ax + b where Q(x) is the quotient.F(1) = Q(1) (1 - 1) (1 + 1) + a(1) + b
{
F(- 1) = Q(- 1) (- 1 - 1) (- 1 + 1) + a(- 1) + b - 1 = a + b
{
- 5 = - a + bSolving, a = 2 and b = - 3
∴ The remainder is 2x - 3.


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