條數唔明點計?

2015-01-08 6:02 am
我想問0.9882 = (0.827/18)/ (0.827/18 + 0.173/M)
M = 315.3 係點計出來?

回答 (2)

2015-01-08 10:59 am
✔ 最佳答案

0.9882 = (0.827/18)/ (0.827/18 + 0.173/M)

右手便分子分母都乘18

=> 0.9882 = (0.827)/ (0.827 + (0.173*18)/M)

=> 0.9882 = (0.827)/ (0.827 + 3.114/M)

右手便分母同左手邊對調
=> (0.827 + 3.114/M) = 0.827 / 0.9882
左手加移至右便變減
=> 3.114/M = (0.827/ 0.9882 ) - 0.827

左手便分母同右手邊對調
=> 3.114/((0.827/ 0.9882 ) - 0.827) = M
撳計算機
=> M= 315.3377

完成,交功課
2015-01-10 7:56 am
0.9882 = (0.827/18)/ (0.827/18 + 0.173/M)
0.9882(0.827/18 + 0.173/M)=(0.827/18)(0.827/18 + 0.173/M)/(0.827 + 0.173/M)
0.0454023+0.1709413/M=0.827/18
M(0.0454023+0.1709413/M)=M(0.827/18)
0.0454023M+0.1709413=0.827M/18
18(0.0454023M+0.1709413)=18(0.827M/18)
0.8172414M+3.0769434=0.827M
0.8172414M+3.0769434-0.8172414M=0.827M-0.8172414M
3.0769434=0.0097586M
0.0097586M/0.0097586=3.0765434/0.0097586
M=315.3


收錄日期: 2021-04-15 17:53:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150107000051KK00118

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