How to solve for k: e^(3200k)=1/2?

2015-01-03 8:36 pm
更新1:

Please show all your work step by step and tell me the right answer.

回答 (3)

2015-01-03 8:38 pm
✔ 最佳答案
take natural logs both sides
ln e^3200k = ln (1/2) = - ln 2
3200k = -ln 2
k = -(ln 2)/3200 = -0.00021661 (approx)
2015-01-03 8:44 pm
e³²⁰⁰ᵏ = ½
3200k = ln(½)
k = ln(½)/3200 ≅ -0.000216608
2015-01-03 8:42 pm
k = -0.000216608


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