1.solve 4-x/3= -1 x=____
2.The sum of 3 consecutive even numbers is420.If the smallest of them is x,which
of the following equations can be used to find the value of x ?(choose one only)
A. x + 2x + 4x = 420
B. 2x+4x+6x=420
C. x+(x+1)+(x+2)=420
D.x+(x+2)+(x+4)=420 Answer:___
3. Simplify (2y2次方+5)-(3-y2次方)
Answer：___________________
數學問題 10point!!!
2014-12-27 10:21 pm
回答 (3)
2014-12-27 10:44 pm
✔ 最佳答案
1. 4-x/3= -1 x/3=5
x=15
2.D
3. (2y^2+5)-(3-y^2)
=2y^2+5-3+y^2
=3y^2+2
^2 = 二次方
參考: ME!!
2014-12-28 2:52 am
1） 4- x/3= -1
4=x/3 -1
5=x/3
15=x
x=15
2）D
3）{(2y)^2+5}-(3-y^2)
=(2xyx2xy+5)-(3-y^2)
=(4y^2+5)-3+y^2
=(4y^2+y^2)+(5-3)
=(4y^2+y^2)+2
4=x/3 -1
5=x/3
15=x
x=15
2）D
3）{(2y)^2+5}-(3-y^2)
=(2xyx2xy+5)-(3-y^2)
=(4y^2+5)-3+y^2
=(4y^2+y^2)+(5-3)
=(4y^2+y^2)+2
2014-12-27 11:07 pm
1. 4- x/3= -1
4=x/3 -1
5=x/3
15=x
x=15
2.D
3.[ (2y)^2+5}-(3-y^2)
=(2xyx2xy+5)-(3-y^2)
=(4y^2+5)-3+y^2
=(4y^2+y^2)+(5-3)
=(4y^2+y^2)+2
4=x/3 -1
5=x/3
15=x
x=15
2.D
3.[ (2y)^2+5}-(3-y^2)
=(2xyx2xy+5)-(3-y^2)
=(4y^2+5)-3+y^2
=(4y^2+y^2)+(5-3)
=(4y^2+y^2)+2
參考: Me
收錄日期: 2021-04-15 17:41:27
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