Integration problem?

2014-12-14 4:37 am
I need some steps as to where to start the integral of 1/(1-y^2) dy.

I do think that this might require trig substitution but its been a while
更新1:

ah crud, I forgot to put in the square root, it should have been sqrt(1/(1-y^2)). I figured that out after I solved the original integrand I posted. Nonetheless, thanks for answering

回答 (1)

2014-12-14 4:38 am
1/(1-y^2) = a/(1-y)+b/(1+y)
find a , b then integrate


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