項數 1 2 3 4 5 6
值 12 25 42 63 88 117
求規律~
請問：當項數為N時，值是多少?
數字規律求解
2014-12-13 5:38 am
回答 (3)
2014-12-13 6:17 am
✔ 最佳答案
記項數 N = T(N) , T(1) = 12 = 4 × 3
T(2) = 25 = 5 × 5
T(3) = 42 = 6 × 7
T(4) = 63 = 7 × 9
T(5) = 88 = 8 × 11
T(6) = 117 = 9 × 13
歸納得 T(N) = (N+3) × (2N+1)
∴ 當項數為N時，值是(N+3)(2N+1).
2014-12-22 3:14 am
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2014-12-19 4:28 pm
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收錄日期: 2021-04-21 22:31:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20141212000016KK03866