因式分解4x平方-y平方-2y-1
因式分解4x平方-9y平方-4x+1
無須講解,需過程
因式分解兩題(國2)
2014-12-10 2:57 am
回答 (3)
2014-12-10 8:52 am
✔ 最佳答案
4X^2 -Y^2 -2Y -1= 4X^2 -(Y^2 +2Y +1)
= (2X)^2 -(Y+1)^2
= [2X +(Y+1)] [2X -(Y+1)]
= (2X+Y+1)(2X-Y-1)
4X^2 -9Y^2 -4X +1
= (4X^2 -4X +1) -9Y^2
= (2X-1)^2 -(3Y)^2
= [(2X-1) +3Y] [(2X-1) -3Y]
= (2X+3Y-1)(2X-3Y-1)
參考: 平方差公式
2014-12-10 5:01 am
TO LCS:筆誤
=(2x+1)(2x+1)-(3y)^2
應為
=(2x-1)(2x-1)-(3y)^2
=(2x+1)(2x+1)-(3y)^2
應為
=(2x-1)(2x-1)-(3y)^2
2014-12-10 3:13 am
4x^2-y^2-2y-1
=4x^2-(y^2+2y+1)
=4x^2-(y+1)^2
=(2x)^2-(y+1)^2
=(2x-y-1)(2x+y+1)
4x^2-9y^2-4x+1
=(4x^2-4x+1)-9y^2
=(2x+1)(2x+1)-(3y)^2
=(2x+1)^2-(3y)^2
=(2x+1-3y)(2x+1+3y)
=4x^2-(y^2+2y+1)
=4x^2-(y+1)^2
=(2x)^2-(y+1)^2
=(2x-y-1)(2x+y+1)
4x^2-9y^2-4x+1
=(4x^2-4x+1)-9y^2
=(2x+1)(2x+1)-(3y)^2
=(2x+1)^2-(3y)^2
=(2x+1-3y)(2x+1+3y)
收錄日期: 2021-04-27 21:33:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20141209000010KK04440