Factorize x^3+27
Hence,Factorize x^3+x^2+4x+30
F.2Maths
2014-11-28 3:34 am
回答 (3)
2014-11-28 4:03 am
✔ 最佳答案
a) x^3+27=x^3+(3)^3
=(x+3)(x^(2)-3x+9)
b)x^3+x^2+4x+30
=x^3+27+x^2+4x+3
=(x+3)(x^(2)-3x+9)+(x+3)(x+1)
=(x+3)(x^2-3x+9+x+1)
=(x+3)(x^2+2x+10)
hope can help u :D
2014-11-27 20:04:04 補充：
打錯了. 最後B部分是(x+3)(x^2-2x+10) 抱歉
參考: own knowledge
2014-11-28 5:10 am
A) x^3+27
=x^3+(3)^3
=(x+3)(x^(2)-3x+9)
B)x^3+x^2+4x+30
=x^3+27+x^2+4x+3
=(x+3)(x^(2)-3x+9)+(x+3)(x+1)
=(x+3)(x^2-3x+9+x+1)
=(x+3)(x^2-2x+10)
=x^3+(3)^3
=(x+3)(x^(2)-3x+9)
B)x^3+x^2+4x+30
=x^3+27+x^2+4x+3
=(x+3)(x^(2)-3x+9)+(x+3)(x+1)
=(x+3)(x^2-3x+9+x+1)
=(x+3)(x^2-2x+10)
2014-11-28 3:36 am
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