You are testing your brandnew Ferrari Testarossa. To see how well the brakes work you accelerate to 100 miles per hour, slam on the brakes, and determine that you brought the car to a stop over a distance of 504 feet. Assuming a constant deceleration you figure that that deceleration is ______________feet per second squared?
I trust that you don't have the courage to try this, but that night you wonder how long it would take you to stop (with the same constant deceleration) if your were moving at 200 miles per hour. Remembering your Calculus you figure out that your stopping distance would be _____________feet.
Question about calculus?
2014-11-26 6:04 pm
回答 (2)
2014-11-26 6:47 pm
100 MPH = 5280/3600 = 146.6* ft/sec...
v² = u² + 2as
0 = (146.6*)² + 2a(504)
a = -21511.1*/1008
a = -23.34 m/sec²
Calculate stopping distance from 200 MPH from the same equation
Calculate stopping time from v = u + at
v² = u² + 2as
0 = (146.6*)² + 2a(504)
a = -21511.1*/1008
a = -23.34 m/sec²
Calculate stopping distance from 200 MPH from the same equation
Calculate stopping time from v = u + at
2014-11-26 6:12 pm
Not calculus really use suvay equations s(distance) v(initial velocity) u(final velocity) a(acceleration) t(time) s=504ft u=100(concert to fts-1) to v=0 v2=u2+2as rearrange anger you have the values and get a then use a as 200 v as 100(again convert) and u as 0 and do the same
參考: As physics
收錄日期: 2021-05-01 15:15:13
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