How to solve
2cosx=1
&
2sinx=-1
HELP ON MATH EQUATION!!?
2014-11-23 1:54 pm
回答 (1)
2014-11-23 1:58 pm
2cosx = 1
cosx = 1/2
x = pi/3 + 2npi or x = 5pi/3 + 2npi for all integers, n
2sinx = -1
sinx = -1/2
x = 7pi/6 + 2npi or x = 11pi/6 + 2npi for all integers, n
cosx = 1/2
x = pi/3 + 2npi or x = 5pi/3 + 2npi for all integers, n
2sinx = -1
sinx = -1/2
x = 7pi/6 + 2npi or x = 11pi/6 + 2npi for all integers, n
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20141123055433AARAjKm