(A)when x^99+k is divided by x+1,the remainder is 1. find the value of k.
(B) Hence,find the remainder when 9^99 is divided by 10.
please show precise steps because the teacher said this self learning question will be assessed in my test ������������
thanks very much����
5分好易攞！difficult remainder q
2014-11-11 5:20 am
回答 (3)
2014-11-11 6:38 am
✔ 最佳答案
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2014-11-10 22:40:10 補充：
最後個哥行 ' the remainder is 3. '
應改為 ' the remainder is -1. '
2014-11-11 14:13:52 補充：
因為??...
http://zh.wikipedia.org/wiki/%E5%A4%9A%E9%A1%B9%E5%BC%8F%E9%95%BF%E9%99%A4%E6%B3%95#.E4.BE.8B
話說佢嘅餘數係...
2014-11-14 11:47 pm
When the remainder becomes negative, borrow one unit from the divisor and add it up to turn it into positive:
-1+10=9, the remainder should be 9.
In fact, the remainder for x^n/10 is either 9 (when n is odd) or 1 (when n is even) only.
-1+10=9, the remainder should be 9.
In fact, the remainder for x^n/10 is either 9 (when n is odd) or 1 (when n is even) only.
2014-11-11 4:59 pm
實數的"除"，餘數不可能是負值的。
收錄日期: 2021-04-11 20:54:04
原文連結 [永久失效]:
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