Pls help
2t(3-2t)=4t(5-t)
方程問題 2t(3-2t)=4t(5-t)
2014-11-07 3:44 am
回答 (4)
2014-11-07 6:17 am
✔ 最佳答案
2t(3 - 2t) = 4t(5 - t)t(3 - 2t) = 2t(5 - t)
3t - 2t² = 10t - 2t²
10t - 3t = 0
7t = 0
t = 0
2014-11-06 23:59:09 補充：
To 「本周之星」：
6t = 20t
t = 0
2014-11-11 6:14 am
當 t = 0:
左式 6t = 6 x 0 = 0
右式 20t = 20 x 0 = 0
因為 0 = 0
所以 6t = 20 t
故 t = 0 為 6t = 20t 之根。
左式 6t = 6 x 0 = 0
右式 20t = 20 x 0 = 0
因為 0 = 0
所以 6t = 20 t
故 t = 0 為 6t = 20t 之根。
2014-11-07 11:49 am
ans=0.5477...
=0.548
=0.548
2014-11-07 4:18 am
移項後
6t-4t^2=20t-4t^2
咦有問題，此式不能成立
2014-11-06 22:44:19 補充：
不必計，6T不等如20T
2014-11-07 08:14:05 補充：
如t=0，那麼0是否等如0?
6t-4t^2=20t-4t^2
咦有問題，此式不能成立
2014-11-06 22:44:19 補充：
不必計，6T不等如20T
2014-11-07 08:14:05 補充：
如t=0，那麼0是否等如0?
收錄日期: 2021-04-15 17:11:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20141106000051KK00087