solve the following initial value problem
1. xy'=y+xcot(y/x) y(pi)=0
2. y'=(x^2y-y)/(y+1) y(3)=-1
3. y'+xy=xy^2 y(0)=2
ODE question!!!
2014-11-06 8:52 pm
回答 (2)
2014-11-07 11:55 pm
2014-11-09 10:28 pm
收錄日期: 2021-04-24 10:32:52
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https://hk.answers.yahoo.com/question/index?qid=20141106000051KK00028