已知三角形ABC垂心H,.....,求ABC面積

∠ECD + ∠EHD = 180° = ∠EHD + ∠BHD ∠BHD = ∠ECD = ∠ACB DH = BH cos(∠BHD) = 1/√2 CH = 1, ∠DCH = ∠BCF = ∠CBF = ∠CBA =45° CD = DH = 1/√2BD = BH sin(∠BHD) = 5 x 7/(5√2) = 7/√2 BC = BD + CD = 8/√2 = 4√2 AD = BD = 7/√2 △ABC = (7/√2)( 4√2)/2 = 14

圖片參考：https://s.yimg.com/rk/AD09210203/o/898921182.jpg

BH=5,CH=1

圖的比例未免也差太多了，還是....??