✔ 最佳答案
1.
係數和=0
有(x-1)之因式
x ^3 - 6x^2 + 11 x - 6=(x-1)(x^2-5x+6)=(x-1)(x-2)(x-3)
2.
係數和=0
有(x-1)之因式
x^3 + 3x ^2 - 4 =(x-1)(x^2+4x+4)=(x-1)(x+2)^2
3.
係數和=0
有(x-1)之因式
6x^3 - 5x^2 - 2 x + 1=(x-1)(6x^2-x-1)=(x-1)(2x-1)(3x+1)
4.
a^4 + 2a^3 + 3a^2 + 2a + 1
2014-11-01 00:27:29 補充:
更正
3.
6x^3 - 5x^2 - 2 x + 1=(x-1)(6x^2+x-1)=(x-1)(2x+1)(3x-1)
2014-11-01 01:08:56 補充:
4.
a^4 + 2a^3 + 3a^2 + 2a + 1 =(a^4+a^3+a^2)+(a^3+a^2+a)+(a^2+a+1)
=a^2( a^2+a+1)+a(a^2+a+1)+(a^2+a+1)
= (a^2+a+1) (a^2+a+1) =(a^2+a+1)^2