特殊因式分解~ 幫我一下…

2014-10-31 7:00 pm
1. x ^3 - 6x^2 + 11 x - 6


2. x^3 + 3x ^2 - 4



3. 6x^3 - 5x^2 - 2 x + 1


4. a^4 + 2a^3 + 3a^2 + 2a + 1

回答 (2)

2014-11-01 8:23 am
✔ 最佳答案
1.
係數和=0
有(x-1)之因式
x ^3 - 6x^2 + 11 x - 6=(x-1)(x^2-5x+6)=(x-1)(x-2)(x-3)

2.
係數和=0
有(x-1)之因式
x^3 + 3x ^2 - 4 =(x-1)(x^2+4x+4)=(x-1)(x+2)^2

3.
係數和=0
有(x-1)之因式
6x^3 - 5x^2 - 2 x + 1=(x-1)(6x^2-x-1)=(x-1)(2x-1)(3x+1)

4.
a^4 + 2a^3 + 3a^2 + 2a + 1

2014-11-01 00:27:29 補充:
更正
3.
6x^3 - 5x^2 - 2 x + 1=(x-1)(6x^2+x-1)=(x-1)(2x+1)(3x-1)

2014-11-01 01:08:56 補充:
4.
a^4 + 2a^3 + 3a^2 + 2a + 1 =(a^4+a^3+a^2)+(a^3+a^2+a)+(a^2+a+1)
=a^2( a^2+a+1)+a(a^2+a+1)+(a^2+a+1)
= (a^2+a+1) (a^2+a+1) =(a^2+a+1)^2
2014-11-01 9:22 am
問前三題代表該念的沒熟,何況題目只用1


收錄日期: 2021-04-27 21:34:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20141031000015KK01096

檢視 Wayback Machine 備份