✔ 最佳答案
If E and F are mutually exclusive, then
Pr(E ∩ F) = 0
Pr(E ∪ F) = Pr(E) + Pr(F)
Note that for any events A and B,
A = (A ∩ B)∪(A ∩ B')
Pr(A) = Pr(A ∩ B) + Pr(A ∩ B')
It is given that Pr(E) = 0.71.
Also, Pr(E ∪F') = 0.84.
Consider
Pr(E ∪ F') = Pr(E) + Pr(F') - Pr(E ∩ F')
Pr(E ∪ F') = Pr(E) + Pr(F') - [Pr(E) - Pr(E ∩ F)]
Pr(E ∪ F') = Pr(E) + Pr(F') - [Pr(E) - 0]
Pr(E ∪ F') = Pr(E) + Pr(F') - Pr(E)
Pr(E ∪ F') = Pr(F')
Therefore,
Pr(F') = 0.84
1 - Pr(F) = 0.84
Pr(F) = 1 - 0.84 = 0.16
2014-10-15 12:48:09 補充:
同學,題目詢問的是 Pr(F) 那是一個 probability,必在0和1之間。
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