solve the system
x1 + x2 = -5
x2 + x3 = 2
x3 + x4 = 5
x1 + x4 = -2
[x1 x2 x3 x4] = ______________+ s_______________ where s is a free variable.
Solve the system?
2014-09-18 5:37 am
回答 (2)
2014-09-19 1:57 am
x1 + x2 = -5
x2 + x3 = 2
x3 + x4 = 5
x1 + x4 = -2
Solution:
No solution
x2 + x3 = 2
x3 + x4 = 5
x1 + x4 = -2
Solution:
No solution
2014-09-18 7:05 am
x1 + x2 = -5 ==> x2 = -x1 -5 ..................... [1]
x2 + x3 = 2 ==> -x1-5 +x3 = 2, ==> x3 = x1+7 ........... [2]
x3 + x4 = 5 ==> x1+7 +x4 = 5, ==> x4 = -x1 -7 ................ [3]
x1 + x4 = -2 , ==> x4 = -x1 -2 ........................... [4]
From [3] & [4], -x1 -7 = -x1-2, ... Not Valid ..
Hence,
NO Solution >==========================< ANSWER
x2 + x3 = 2 ==> -x1-5 +x3 = 2, ==> x3 = x1+7 ........... [2]
x3 + x4 = 5 ==> x1+7 +x4 = 5, ==> x4 = -x1 -7 ................ [3]
x1 + x4 = -2 , ==> x4 = -x1 -2 ........................... [4]
From [3] & [4], -x1 -7 = -x1-2, ... Not Valid ..
Hence,
NO Solution >==========================< ANSWER
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https://hk.answers.yahoo.com/question/index?qid=20140917213753AAmI2yN