求lim┬(x→0)〖(〖sin〗^2 x/2)/x^2
求
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求lim┬(x→0)〖(〖sin〗^2 x/2)/x^2
2014-09-16 5:35 pm
回答 (1)
2014-09-16 5:58 pm
✔ 最佳答案
Sollim(x->0)_Sin^2 (x/2)/x^2
=(1/2)*lim(x->0)_2Sin^2 (x/2)/x^2
=(1/2)*lim(x->0)_(1－Cosx)/x^2 0/0 type
=(1/2)*lim(x->0)_Sinx/(2x) . 0/0 type
=(1/2)*lim(x->0)_Cosx/2
=1/4
收錄日期: 2021-04-30 18:39:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140916000016KK03569