Recurring Decimals - (F.3)

2014-09-06 4:07 am
Not really a F.3 question.

I just want to see if there's way to figure the number of digits in the recurring part of a recurring decimal, just by looking at the fraction.

e.g
1/3 = 0.333333333...
Any simple methods to determine that "there is 1 digit in the recurring part" just by looking at the fraction 1/3.



Please help. Thank you!!!

回答 (1)

2014-09-11 4:06 am
✔ 最佳答案
There is no way to determine in general.

A rational number would result in either a fixed or recurring decimal.

There are infinite number of choices in the denominators.

2014-09-05 21:25:10 補充:
Nonetheless, for some common cases, you can have a note:

For example, 142857 refers to the recurring part with denominator as a multiple of 7.

2014-09-10 20:06:58 補充:
There is no way to determine in general.

A rational number would result in either a fixed or recurring decimal.

There are infinite number of choices in the denominators.

For example, as your case, there is one digit in the recurring decimal 0.3333333333 which is 1/3.

However, for 0.22222222222, there is also one digit here, but it is 2/9.

Of course for 1/3 you can view it as 3/9 and claim that every recurring decimal form by dividing by 9 would result in one-digit recurring.

However, for a more general situation, like you ask for 2-digit recurring, there are many different patterns of recurring with 2 digits, in general there should be no way to give a rule.

Still, this is a nice question to ask, thanks for your input.


圖片參考:https://s.yimg.com/rk/HA00430218/o/545489186.jpg


收錄日期: 2021-04-18 00:01:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140905000051KK00094

檢視 Wayback Machine 備份