更新1:
My approach is like this: Normal reaction acting on the wedge by block = Force acting on the block = mg cos30 By basic geometry, horizontal component of the force= sin30 mg cos30 Acceleration= 1/2(mgcos30)/(M)=1/2(mgcos30)/(2m)
更新2:
Considering the motion of the block: s=0.5 at^2+ut H/sin30=1/2(0.5g)(t^2) H=1/8(gt^2) t= 2sqrt(2H/g) By v=u+at, v=at=1/2(gcos30)(2sqrt(2H/g) =sqrt(6gH)/4 =1.918sqrtH m/s
更新3:
By s=0.5at^2+ut distance= 0.5(1/4)gcos30 (8H/g) = gcos30H/g =cos30H =0.866H m Anyone can tell me whether I am correct or not? Thanks a lot!