physics momentum

2014-07-30 10:30 am
1. http://s1353.photobucket.com/user/s031026/media/15_zps0622402e.jpg.html

why can't (2) be the subsequent motion?

2. http://s1353.photobucket.com/user/s031026/media/14_zps06aa618e.jpg.html

could you pls explain (3)?

3. http://s1353.photobucket.com/user/s031026/media/13_zpscc0bfb2e.jpg.html

how can i calculate theta without knowing the initial speed of the box?

4. Is it true that a person with greater weight will experience more serious injury in an impact?

回答 (2)

2014-07-30 4:19 pm
✔ 最佳答案
1. In process (2), the total kinetic energy completely vanished. It is possible only if the collision is perfectly inelastic.

2. Initial momentum before collision = (2m/3)[sqrt(2gh1)]
where m is the mass of ball A.
Total final momentum after collision
= (2m/3).[sqrt(2gh1)] + (2m/3)[sqrt(2gh1)]
= (4m/3).[sqrt(2gh1)]
Momentum seems NOT conserved.

3. I don't think you could. The initial speed of the box is necessary in claculating angle theta.

4. I suppose you are asking for the situation when a person of larger mass collidies with one with a lower mass.

In this case, the impact forces acting on both of them are the same.

2014-07-30 22:50:23 補充:
Your suppl questions:
1. Air pucks collision cannot be perfectly inelastic.

2014-07-30 22:52:56 補充:
2. The masses of ball A and B are m and 2m respectively.
Thus their corresponding momenta are (m).(2/3)[sqrt(2gh1)] and (2m).(1/3)[sqrt(2gh1)]
2014-08-08 6:21 am
may i ask why initial momentum before collision is (2m/3)[sqrt(2gh1)] but not m[sqrt(2gh1)]? hope you will see this thanks!


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