use L'Hospitals Rule, if applicable to find limits: 1) lim x-->1 (x^2-1)/x+1 2) lim x-->0 (1-cosx)/secx?

2014-07-27 12:30 am
For 1, I cannnot apply the rule because if you plug in 1 into x you actally get a number, 0/2=0 correct? or no?

for 2, same thing, you cannot apply because you end up getting 0/1=0
correct?

回答 (1)

2014-07-27 12:31 am
TRUE


收錄日期: 2021-04-30 23:56:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20140726163029AAP4sRJ

檢視 Wayback Machine 備份