Let f(x)= x^3-x^2+x-3 and let g be the inverse of f
What is the value of g'(3)
Derivative help?
2014-07-25 2:44 pm
回答 (2)
2014-07-25 2:47 pm
f'(x)=3x^2-2x+1
g'(x)=1/(3x^2-2x+1)
g'(3)=1/22
g'(x)=1/(3x^2-2x+1)
g'(3)=1/22
2014-07-25 2:47 pm
An inverse is not the same as a derivative. So, which one are you talking about?
When you figure that out, then sub "3" in for g, or g', or whatever it's suppose to be and then do the arithmetic.
When you figure that out, then sub "3" in for g, or g', or whatever it's suppose to be and then do the arithmetic.
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