✔ 最佳答案
咁諗啦...
先假設遊戲在1回合後結束,
2人=>2/3 (1win)
3人=>1/3 (1win)
4人=>1/3 (1win)
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假設遊戲在2回合後結束,
2人=>(1/3)(2/3) (draw*1win)
3人=>(1/9)(1/3)+(1/3)(1/3) (draw*1win + 1lose*1win)
4人=>(1/27)(1/3)+(1/3)(1/3)+(2/9)(1/3) (draw*1win + 1lose*1win + 2lose*1win)
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假設遊戲在3回合後結束
2人=>(1/3)(1/3)(2/3) (draw*draw*1win)
3人=>(1/9)(1/9)(1/3)+(1/9)(1/3)(1/3)(2) (draw*draw*1win + draw*1lose*1win + 1lose*draw*1win)
4人...
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如果有心機就繼續啦...因為題目可以無限個人...個期望值好煩