✔ 最佳答案
電子式測溫器,非電阻式測溫器:A=amper, t=sec, R=ohm, m=masss=比熱=1, T1,T=溫度, k=ms/0.24A^2*t
(1) 原本方程式H=0.24A^2*R*t=m*s*(T-T1)=> R(T)=(ms/0.24A^2*t)*(T-T1)=k*(T-T1)R(100)=k(100-T1)=0.4R(90)=k(90-T1)=0.6=> k=-1/50, T1=120=> R(T)=(120-T)/50
(2) 修改方程式R(T)=(T2-T)/k2R(90)=(T2-90)/k2=0.4R(100)=(T2-100)/k2=0.4*(0.4/0.6)=0.4*2/3=0.8/3=> k2=75, T2=120
(3) 變更元件: m,s,t=固定值k=ms/0.24A^2*t => k2/k=(A/A2)^2A2^2=A^2*(k/k2)=A^2*(50/75)=A^2*(2/3)=> A2=A*√(2/3)=0.8165*A=電流減少為原來電流的0.8165倍